LeetCode 36. Valid Sudoku
Description
Determine if a 9x9 Sudoku board is valid. Only the filled cells need to be validated according to the following rules:
- Each row must contain the digits
1-9
without repetition.- Each column must contain the digits
1-9
without repetition.- Each of the 9
3x3
sub-boxes of the grid must contain the digits1-9
without repetition.A partially filled sudoku which is valid.
The Sudoku board could be partially filled, where empty cells are filled with the character
'.'
.
验证数独
Example 1:
Input: [ ["5","3",".",".","7",".",".",".","."], ["6",".",".","1","9","5",".",".","."], [".","9","8",".",".",".",".","6","."], ["8",".",".",".","6",".",".",".","3"], ["4",".",".","8",".","3",".",".","1"], ["7",".",".",".","2",".",".",".","6"], [".","6",".",".",".",".","2","8","."], [".",".",".","4","1","9",".",".","5"], [".",".",".",".","8",".",".","7","9"] ] Output: true
Example 2:
Input: [ ["8","3",".",".","7",".",".",".","."], ["6",".",".","1","9","5",".",".","."], [".","9","8",".",".",".",".","6","."], ["8",".",".",".","6",".",".",".","3"], ["4",".",".","8",".","3",".",".","1"], ["7",".",".",".","2",".",".",".","6"], [".","6",".",".",".",".","2","8","."], [".",".",".","4","1","9",".",".","5"], [".",".",".",".","8",".",".","7","9"] ] Output: false Explanation: Same as Example 1, except with the 5 in the top left corner being modified to 8. Since there are two 8's in the top left 3x3 sub-box, it is invalid.
Note:
- A Sudoku board (partially filled) could be valid but is not necessarily solvable.
- Only the filled cells need to be validated according to the mentioned rules.
- The given board contain only digits 1-9 and the character ‘.’. The given board size is always 9x9.
判断数独板是否有效。
注:
一个数组板可以是有效但是无解的。
Solution
根据题意只需要判断数独板中给出的数字在行列和3x3格子中是否有重复即可。而不需要判断是否可以解。
func isValidSudoku(board [][]byte) bool {
// 用于标记第x列已使用的数字
colUsed := [9][9]bool{}
// 用于标记3x3小方格已使用的数字
subBoxUsed := [3][3][9]bool{}
for row := 0; row < 9; row++ {
// 用于标记当前行已使用的数字
rowUsed := [9]bool{}
for col := 0; col < 9; col++ {
b := board[row][col]
if b == '.' {
continue
}
num := b - '0' - 1
// 检查数字是否已使用
if rowUsed[num] || colUsed[col][num] || subBoxUsed[row / 3][col / 3][num] {
return false
}
// 标记为已使用
rowUsed[num] = true
colUsed[col][num] = true
subBoxUsed[row / 3][col / 3][num] = true
}
}
return true
}